Physics, asked by XxItsDivYanShuxX, 2 months ago

Two point charges qA = 3 µC and qB= –3 µC are located 20 cm apart in a vacuum. (i) What is the electric field at the midpoint O of the line AB joining the two charges? (ii) If a negative test charge of magnitude 1.5 × 10–9 C is placed at this point, what is the force experienced by the test charge?​

Answers

Answered by firdous41
1

Explanation:

Electric field is the force experienced by a test charge that has a value of +1.

Answered by rithanyaa4
11

Answer:

(a) The situation is represented in the given figure. O is the mid-point of line AB.

Distance between the two charges, AB=20cm

∴AO=OB=10cm

Net electric field at point O=E

Electric field at point O caused by +3 C charge,

E1=4π∈0(AO)23×10−6=4π∈0(10×10−2)23×10−6N/C along OB

Where,

∈0= Permittivity of free space

4π∈01=9×109Nm2C−2

Magnitude of electric field at point O caused by - 3 C charge,

E2=∣∣∣∣∣4π∈0(OB)2−3×10−6∣∣∣∣∣=4π∈0(10×10−2)23×10−6N/C along OB

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