Two point charges qA = 3 µC and qB= –3 µC are located 20 cm apart in a vacuum. (i) What is the electric field at the midpoint O of the line AB joining the two charges? (ii) If a negative test charge of magnitude 1.5 × 10–9 C is placed at this point, what is the force experienced by the test charge?
Answers
Answered by
1
Explanation:
Electric field is the force experienced by a test charge that has a value of +1.
Answered by
11
Answer:
(a) The situation is represented in the given figure. O is the mid-point of line AB.
Distance between the two charges, AB=20cm
∴AO=OB=10cm
Net electric field at point O=E
Electric field at point O caused by +3 C charge,
E1=4π∈0(AO)23×10−6=4π∈0(10×10−2)23×10−6N/C along OB
Where,
∈0= Permittivity of free space
4π∈01=9×109Nm2C−2
Magnitude of electric field at point O caused by - 3 C charge,
E2=∣∣∣∣∣4π∈0(OB)2−3×10−6∣∣∣∣∣=4π∈0(10×10−2)23×10−6N/C along OB
∴
BE A FOLLOWER IN BRAINLY
Similar questions