Question

Two point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude of the electric force. The constant k = 8.988 x 109

Answer 1

Answer:

−2 = 9 x 109 Nm2C−2.

Coulomb's law – problems and solutions 1

Known :

Charge A (qA) = +8 μC = +8 x 10-6 C

Charge B (qB) = ­-5 μC = -5 x 10-6 C

k = 9 x 109 Nm2C−2

The distance between charge A and B (rAB) = 10 cm = 0.1 m

Wanted : The magnitude of the electric force

Solution :

Formula of Coulomb’s law :

Coulomb's law – problems and solutions 2

The magnitude of the electric force :

Coulomb's law – problems and solutions 16