Question

Two point charges repel with a force of 4.5 milli Newton . On doubling on of the charges and altering their separation by 5 cm, the force of repulsion is 1.6 milli Newton. What was their original separation *
1 point
20 cm
25 cm
40 cm
50 cm
Answer needed ASAP

Answer 1

Explanation:

F= Kq1q2/r^2

1.6= kq^2 /9

Since k= 9x10^9

1.6= 10^9xq^2

q= 4x10^-5 C

Hope it helps.

Answer 2

Answer:

20 cm

Explanation:

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