two point charges when separated by a distance in air repel by a force of 100N. When these charges are now placed in a medium of dielectric constant 20, find the new force.
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Answered by
0
Answer:
F=20*100=200 N
Explanation:
when a medium of dielectric is placed then the force increases respectively.
Answered by
2
answer : new force would be 5N
let q₁ and q₂ are two charges when seperated by a distance r in air repel by a force of 100N.
F = 100 = kq₁q₂/r² ..........(1)
a/c to question, when these charges are now placed in a medium of dielectric constant, d = 20.
F' = kq₁q₂/dr² = F/d
from equation (1) we get,
F' = 100/20 = 5N
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