Question

Two point masses 2kg connected by weightless rod 50cm calculate radius of gyrations

Answer 1

Centre of mass:

XCM=m1x1+m2x2/m1+m2 =(2×0)+(10×1.2)2+10

=1 m

Determination moment of inertia:

r1=XCM

= 1 m

r2=L−XCM

= 1.2 −1

= 0.2 m

I=(m1)(r1)2+(m2)(r2)2

=(2)(1)2+(10)(0.2)2

= 2.4 kg.m2

Answer:

Moment of inertia, I=2.4 kg.m2