Two point masses at a given distance exert a gravitational interaction force on each other having a magnitude F. If one mass is doubled the other mass is halved and the distance between them is tripled, the resulting interaction force magnitude.
(a) F (b) 4F (c) 4F/9 (d)F/9
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F = GmM/r²
F = G (2m)(M/2)
(3r)²
Both 2s get cancelled out and
The value of (3r)² = 9r²
Separate the 9 from the equation to get -
GmM
r² × 1/9
And then put the values
F × 1/9 = F/9 is your answer.
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