Question

Two point masses each equal to 1 kg attract one another with a force of 10n the distance bet two point masses is
a.8 cm
b.80cm c)0.8cm
d.0.08 cm

Answer 1

Answer:

Correction: The value of Force is 10⁻¹⁰ N

Two masses attract each other with the help of a force called Gravitation Force. According to Gravitation Force, the expression is given as:

$F = \dfrac{GMm}{r^2}$

Here, 'G' is Universal Gravitation constant, 'M' and m are masses of the objects, 'r' is the distance between the two objects.

According to the question, F = 10⁻¹⁰ N, Masses are 1 kg each. Distance between the masses are to be found. Substituting in the formula we get,

$\implies 10^{-10} = \dfrac{6.67 \times 10^{-11} \times 1 \times 1}{r^2}\\\\\implies r^2 = \dfrac{6.67 \times 10^{-11}}{10^{-10}}\\\\\implies r = \sqrt{6.67 \times 10^{-1}} = \sqrt{0.667}\\\\\implies r = 0.8 \: m\: or\: 80 \: cm$

Therefore the distance between the two point masses are 80 cm.

Answer 2

Answer:

80cm

Explanation:

Two masses attract each other with the help of a force called Gravitation Force. According to Gravitation Force, the expression is given as:

F = \dfrac{GMm}{r^2}F=

r

2

GMm

Here, 'G' is Universal Gravitation constant, 'M' and m are masses of the objects, 'r' is the distance between the two objects.

According to the question, F = 10⁻¹⁰ N, Masses are 1 kg each. Distance between the masses are to be found. Substituting in the formula we get,

\begin{lgathered}\implies 10^{-10} = \dfrac{6.67 \times 10^{-11} \times 1 \times 1}{r^2}\\\\\implies r^2 = \dfrac{6.67 \times 10^{-11}}{10^{-10}}\\\\\implies r = \sqrt{6.67 \times 10^{-1}} = \sqrt{0.667}\\\\\implies r = 0.8 \: m\: or\: 80 \: cm\end{lgathered}

⟹10

−10

=

r

2

6.67×10

−11

×1×1

⟹r

2

=

10

−10

6.67×10

−11

⟹r=

6.67×10

−1

=

0.667

⟹r=0.8mor80cm

Therefore the distance between the two point masses are 80 cm.