Question

two point masses each equal to 1 kg attract one another with a force of 10^-9 kg - wt .
the distance b/w the two point masses is approximately ? i want answer with explaination........please answer........

1 - 8.2cm
2 - 0.8cm
3 - 80cm
4 - 0.08cm

Answer 1

Answer:

1. 8.2 cm

Explanation:

F = $\frac{Gm_{1}m_{2}  }{r^{2} }$

So, r = $\sqrt{\frac{Gm_{1}m_{2}  }{F} }$

= $\sqrt{\frac{6.67 \times 10^{-11} \times 1 \times 1 }{10^{-9} \times 9.8 } }$

= 0.082 m = 8.2 cm