Question

Two point masses 'm' are kept 'r' distance apart .What Will be the potential at 0.25r distance from any one masses towards the other masses?

Answer 1

Answer: $V=-\frac{16}{3}\frac{Gm}{r}$

Explanation:

The gravitational potential is given by:

$V=-G\frac{m}{r}$

here, m is mass of the object, r is the distance from the object where potential is to be found and G is the gravitational constant $= 6.67 \times 10^{-11}N.m^2/kg^2$

we need to find the potential at 0.25 r from one mass

$V_1=-G\frac{m}{0.25r}=-4\frac{Gm}{r}$  

Potential due to other mass which is at 0.75 r distance:

$V_2=-G\frac{m}{0.75r}=-\frac{4}{3}\frac{Gm}{r}$  

Net potential:

$V=V_1+V_2= -4\frac{Gm}{r}-\frac{4}{3}\frac{Gm}{r}= -\frac{16}{3}\frac{Gm}{r}$

Answer 2

Explanation:

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