Two point masses m are kept r distance apart. What will be the potential at 0.25r distance from any one mass towards the other mass
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Answered by
15
it should be the answer
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Answered by
3
Answer:
answer is 16Gm/ 3R
Explanation:
V1= -Gm/R/4 = -4Gm/R
V2= -Gm/3R/4 = -4Gm/3R
V=V1+V2
= -4Gm/R -4Gm/3R
=-12Gm-4Gm/3R
=-16Gm/3R
Hope it will help you.
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