Question

two point masses M1 and M2 separated by distance are revolving under mutual force of attraction ratio of their respective Kinetic energies will be​

Answer 1

Answer:

M2/M1.

Explanation:

Since, from the question we do not know the masses which are M1 and M2 given. Hence, as they are separated by a distance of d and are revolving under mutual force of attraction. Therefore, the center of gravity of the point where it will be in equilibrium will be at a point x in the somewhere middle M1(-x) + M2(d-x)/(M1 + M2) =0 which will be M2d=(M1+M2)x or x=M2d/(M1+M2) and the value of distance from the other end will be M1d/(M1+M2).

So, the kinetic energy ratio will be 1/2(I1)ω^2/ 1/2(I2)ω^2 or I1/I2 or M1(M2d/(M1+M2))^2/M2(M1d/(M1+M2))^2 or the ratio on solving we will get that M2/M1.