Question

two point masses of 4 kg and 2 kg kept at a distance
olm in air attract each other by a force F.
These
two masses are now dipped in kerosene keeping
the distance same What is the force of attraction
between the masses in kerosene?​

Answer 1

$\huge\red{\boxed{\orange{\mathcal{\overbrace{\underbrace{\fcolorbox{red}{pink}{\underline{\red{❥Answer࿐}}}}}}}}}$

Answer

Mass of first body \(M= 4\ kg\)

Mass of second body \(m= 2\ kg\)

Distance between bodies \(r = 1\ m\)

Gravitational constant \(G = 6.67\times 10^{-11}\ N\ m^{-2}kg^{-2}\)

If force of gravitation between two masses is found to be \(F\) in air, then the force of gravitational force will be same when masses are dipped in kerosene at same distance. This is because force of gravitation remains constant in every medium.

As, \(F=\frac{GMm}{r^2}=6.67\times 10^{-11}\times \frac{4\times 2}{(1)^2}\)

Hence, magnitude

hi how r u.

Answer 2

Answer:

Answer

Mass of first body \(M= 4\ kg\)

Mass of second body \(m= 2\ kg\)

Distance between bodies \(r = 1\ m\)

Gravitational constant \(G = 6.67\times 10^{-11}\ N\ m^{-2}kg^{-2}\)

If force of gravitation between two masses is found to be \(F\) in air, then the force of gravitational force will be same when masses are dipped in kerosene at same distance. This is because force of gravitation remains constant in every medium.

As, \(F=\frac{GMm}{r^2}=6.67\times 10^{-11}\times \frac{4\times 2}{(1)^2}\)

Hence, magnitude

hi how r u.

Step-by-step explanation:

please mark me as branillest