Question

two points A (3, 4) and B (5,-2 ) are given find the point P such that PA is equal to PB and area of triangle ABC is equal to 20
*note that triangle ABC is not a right angled triangle
plzzz help me to solve this problem

Answer 1

Answer:

y= 3, x = 10

Step-by-step explanation:

(1/2)|x(4-(-2)+3(-2-y)+5(y-4)|=20

6x-26+2y=40

y + 3x=33-------(1)

by formula of distance between two points

{(x-3)^2  + (y-4)^2 }^(1/2) = {(x-5)^2  + (y+2)^2 }^(1/2)

5-6x-8y =29-10x+4y

4x-12 = 4

x- 3y =1 -----------(2)

from eq. (1) & (2)

y= 3, x = 10