Question

Two points a and b are at a distance of 5 cm are each at a potential of 10v. What will be the work done to move a positive charge of 1c from a to b

Answer 1

Given:

Two points a and b are located at a distance of 5 cm from each other and each of them are at a potential of 10 volts.

To find:

Work done in moving a positive charge of 1 C from a to b.

Concept:

Potential difference is defined as the work done to transport a unit positive charge from one point to another.

In other words , we can say that potential difference is actually the ratio of the work done to the charge transported.

Calculation:

$\therefore\sf{potential \: difference = \dfrac{work}{charge} }$

$\sf{ = > V_{b} - V_{a} = \dfrac{work}{charge} }$

$\sf{ = > 10 - 10 = \dfrac{work}{1} }$

$\sf{ = > 0 = \dfrac{work}{1} }$

$\sf{ = > work = 0 \: joule }$

So final answer:

$\boxed{ \sf{ \large{ work \: done= 0 \: joule }}}$

Answer 2

Given ,

• The electric potential at point a and b is 10 v
• The charge is 1 C

We know that ,

$\large \sf \fbox{V_{b} - V_{ a } = \frac{ W_{ab} }{q} }$

Thus ,

$\sf \mapsto 10 - 10 = \frac{W }{1} \\ \\ \sf \mapsto W = 0 \: \: joule$

$\therefore \sf \underline{The \: work \: done \: to \: move a \: unit \: charge \: from \: point \: a \: to \: b \: is \: 0 \: joule </p><p>}$