Question

two points A and B are on the same side of a tower and in the same straight line with its base the angles of depression of these points from the top of the tower and 60 degree and 45 degree respectively if the height of the tower is 15 M then find the distance between these points

Answer 1

here's your answer
Best of luck

Answer 2

Answer: The distance between the points is 5(3-√3) unit

Step-by-step explanation:

Since, by the below diagram,

We can write,

$tan 60^{\circ}=\frac{15}{AO}$

$AO=\frac{15}{tan60^{\circ}}$

$AO = \frac{15}{\sqrt{3}}=5\sqrt{3}$

Also, Again by the diagram,

$tan45^{\circ}=\frac{15}{BO}$

$BO=\frac{15}{tan45^{\circ}}=15$

Hence, the distance between A and B is,

$OB-OA=15- 5\sqrt{3}= 5(3-\sqrt{3})\text{ unit}$

Hence, The distance between the points is 5(3-√3) unit