Two points A and B are on the same side of a tower. They measure the angle of
elevation of the top of the tower as 30° and 60° respectively. If the height of the tower is
of elevation
80 m, find the distance between them.
bon the angle of elevation of the Sun is 45°, is found to
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Let CD is the building A and B are two given point using horizontally on the same side of building.
In △DBC,
tan 60˚ = DC/CB
√3 = 10/y …..(1)
In △DCA, tan 30˚ = DC/CA
1/√3 = 10/(x + y) ….(2)
From (1), put y = 10/√3 in (2), we get
1/√3 = 10/(x + 10/√3)
1/√3 = 10√3/(√3x + 10)
30 = √3x + 10
x = 20/√3
x = 11.55 m
Hence, distance between two points A and B is 11.55 m.
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