Two points a and b lie along a line at a distance of 120km apart. P and q start at the same time from a and b with speeds 40km/h and 60km/h respectively. They travel towards each other and after their meeting for the first time, they then go in reverse directions and also interchange their speeds. These speeds are continued in their further journey. After reaching their respective starting points, they reverse their directions of travel and proceed towards each other again. The time taken by them to meet each other 2nd time is
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The second train has travelled 120 km more than the first train only because the speed of the second train is 10 km/h. more than the first train and their starting time is same.
Time taken by the second train to cover 120 kms with the surplus speed of 10 km/h
=12010=1212010=12 hrs
i.e. time, taken by the both train before meeting point in opposite direction = 12 hrs.
Their relative speed in oppo. direction
=(50+60)(50+60) km/h = 110 km/hr
Total distance covered by them
=12×11012×110= 1320
So the distance between A and B= 1320 km
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