Two points A B in Space f-cordinate (2,-1,3) (4,2,5).Find vector AB.
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♠ ANSWER :
Vector AB = (2i^ + - 1 j^ + 3 k^) ( 4i^ + 2j^ +5k^)
➡️ 8 - 2+ 15
➡️ 21.
Vector AB = (2i^ + - 1 j^ + 3 k^) ( 4i^ + 2j^ +5k^)
➡️ 8 - 2+ 15
➡️ 21.
Answered by
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AB =√ (B - A)
Subtraction will be there corresponding elements in space set
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