Question

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of Oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations of two points? 38 [AIPMT (Prelims)-2008] (1) (2) 2 QU 39 (3) (4) T

Answer 1

The phase difference between the oscillations of two points is 2.093

Explanation:

Given path difference = 15 m - 10 m = 5 m

The time period of oscillation T= 0.05 s.

Frequency,$f =\frac{1}{T} =\frac{1}{0.05} =20 Hz$

Velocity of wave v= 300 m/s

So wavelength,$\lambda=\frac{v}{f} =\frac{300 m/s}{20 Hz} =15 m$

To calculate the phase difference use relation between path and phase difference,

Phase difference  $=\frac{2\pi }{\lambda}$ × path difference

Substitute the given values, we get

Phase difference $=\frac{2\pi }{15 m} (5 m)$

Phase difference$=\frac{2\pi }{3}=2.093]$

Thus, phase difference is 2.093.

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Answer 2

Answer:

this will help you....