Two points charges Qa= -2 uc ,Qb=-2uc are located at (-5,0,0)cm
and (5,0,0)cm respectively.what is the force on charge 1 uc place at (0,0,0)cm.
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Answer:
Explanation:F=QIQ2/R^2
F1=KX2/25=720i^+720i^=1440i^
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