Physics, asked by kasamakash5555, 9 months ago

two points charges repel each other with A force of 100N one of charges is increased by 10% and the other is reduced by 10% the new force of repulsion at the same distance would be

Answers

Answered by shifnamongam

1

Answer is .,

100=kq1q2/r^2. And

F=(1.1q1)(.9q2)/r²

F/100=.99

F=99N

Pls brainlist

Answered by Genetdestaw4

0

Answer:

Expl100=kq1q2/r^2. And

F=(1.1q1)(.9q2)/r²

F/100=.99

F=99N

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