Question

Two points P and are maintained at the potentials of 10V and -4V respectively. The work done in moving 100 electrons from P to is


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Answer 1

Answer ❤

2.24*10-16 J

Hope its help u ❤

Answer 2

$\displaystyle\large\underline{\sf\red{Given}}$

✭ $\displaystyle\sf n = 100$

✭ $\displaystyle\sf V_1 = 10 \ V \ (Initial)$

✭ $\displaystyle\sf V_2 = -4 \ V \ (Final)$

$\displaystyle\large\underline{\sf\blue{To \ Find}}$

◈ The work done?

$\displaystyle\large\underline{\sf\gray{Solution}}$

So here we shall use the below mentioned formulas,

$\displaystyle\sf \underline{\boxed{\sf q = ne}}$

$\displaystyle\sf\underline{\boxed{\sf V = \dfrac{W}{q}}}$

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$\underline{\bigstar\:\textsf{According to the given Question :}}$

Considering e to be 1.6 × 10‾¹⁹

➝ $\displaystyle\sf q = ne$

➝ $\displaystyle\sf q = 100\times 1.6\times 10^{-19}$

➝ $\displaystyle\sf \purple{q = 1.6\times 10^{-17} \ C}$

So now,

➳ $\displaystyle\sf V = \dfrac{W}{q}$

➳ $\displaystyle\sf V_{in} - V_{fi} = \dfrac{w}{q}$

➳ $\displaystyle\sf 10-(-4) = \dfrac{w}{1.6\times 10^{-17}}$

➳ $\displaystyle\sf 14 = \dfrac{w}{1.6\times 10^{-17}}$

➳ $\displaystyle\sf 14\times 1.6\times 10^{-17} = w$

➳ $\displaystyle\sf \pink{w = 22.4\times 10^{-17} \ J}$

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