Question

Two points P and Q are 9 cm apart. A circle of radius 5.1 cm passes through P and Q.
Calculate the distance of its centre from the chord PQ.
pls help urgent

Answer 1

Solution:

Radius of circle = 5.1 cm

Length of chord P Q= 9 cm

Let O be the center of the circle.

Draw OM ⊥ P Q.

PM = M Q=$\frac{9}{2}=4.5$ cm →→[ ⊥ from the center to the chord bisects the chord]

In Δ O MP

OP²= OM² + PM²→→[By Pythagoras theorem]

(5.1)²= (OM)² + (4.5)²

26.01 - 20.25= (OM)²

(OM)²= 5.76

OM= √5.76

OM= 2.4 cm

Distance from the center to chord PQ= 2.4 cm