Question

Two points P and Q are maintained at the potential
10 V and -4 V respectively. The work done in moving
100 electrons from P to Q is. . (Chp.2)​

Answer 1

V=W/Q

POTENTIAL DIFFERENCE = 10-(-4)= 14V

CHARGE ON 1 ELECTRON = 1.6×10^-19 C

CHARGE ON 100 ELECTRONS = 1.6×10^-17C

WORK DONE = 14 × 1.6 ×10^-17=2.24×10^-16 Joules

Answer 2

Answer:

The work done in moving 100 electrons from P to Q is $2.24 * 10^{-16} Joules$

Explanation:

Two points P and Q are maintained at the potential

10 V and -4 V respectively.

According to question we need to find the work done in moving 100 electrons from the point P to the point Q.

Charge of an electron = $1.6 * 10^{-19} C$

So the charge of 100 electrons = $1.6 * 10^{-17} C$

Potential difference between P and Q is = $[10-(-4)]V = 14V$

Work done = Potential difference * Charge of particle

$W = V * Q$

So the work done in moving 100 electrons from P to Q is = $[14 * 1.6 * 10^{-17} ] = 2.24 * 10^{-16} Joules$

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