Question

Two polaroids are kept crossed to each other.now one of them is rotated through an angle of 45∘ the percentage of incident light now transmitted through the system is :

Answer 1

25 percent (by malus law)

Answer 2

Two polaroids are kept crossed to each other. Now one of them is rotated through an angle of $45^o$ the percentage of incident light transmitted through the system is 25%

EXPLANATION:

Let the intensity of the unpolarised light be Io, hence the intensity of the $1st$ polaroid is $I_{0} / 2$. On rotating through $45^0$, the intensity of light from the $2nd$ polaroid is,

$I=\left(I_{0} / 2\right)\left(\cos 45^{\circ}\right)^{2}$

$=I_{0} / 2(I 2 / \sqrt{2})^{2}$

$=I_{0} / 4$

$=\mathrm{I}=25 \% \text { of } \mathrm{I}_{0}$

Therefore the percentage of light transmitted through the system is $25 \% \text { of } I_{0}$

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