Math, asked by Aditya1l, 1 year ago

two poles 15 m and 30 m high stands up right in the playground. If their feet are 36 M apart, find the distance between their tops.

Answers

Answered by abheshek040202

The dist between their tops is 39 m
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Aditya1l: explain it

Aditya1l: I didn't understand

abheshek040202: The dist between the poles is 36 m and the taller pole is 15 m more tall than the short pole so to find dist between the tops which is slanting a triangle is formed and by pythagoras theorem we take dist =root of (15^2 + 36^2) and the ans is 39 m. Did you understand?

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abheshek040202: did you understand?

Aditya1l: yes

Answered by Arnadeep11

Answer: 39m

➡ Given :-

→ Two poles AB and CD are stand upright on the playground of 15m and 30m respectively.

→ Distance between the feet of two poles (BC) is 36m.

➡ To find:-

→ Distance between the top of the two poles (AC).

➡ Construction :-

→ Draw a line AE CD.

➡ Solution :-)

=> AE = BC = 36m.

And,

=> CE = CD - ED.

=> CE = CD - AB. [ ED = AB]

=> CE = 30 - 15

=> CE = 15m.

▶ Now,

↪ In ∆AEC,

=> AE CD.

→ ∆AEC is a right angled triangle.

▶ Therefore, By Pythagoras' theorem, we get

=> AC² = AE² + CE².

=> AC² = (36)² + (15)².

=> AC² = 1296+ 225.

=> AC² = 1521.

=> AC = √1521

= 38m.

✔✔ Hence, the Distance between the top of the two poles is 38m. ✅✅

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