Question

Two poles 15m high and 6m high are placed opposite to each other across a 8m long
road. Find the distance between their tops.​

Answer 1

Solution :

Let the poles be Pole A and pole B respectively .

Height of pole A = 15 m

Height of pole B = 6 m.

We can easily observe that , height of pole A is greater than the height of pole B .

This is by an extent of 9 m .

Now , the distance between the base of the poles is 8 m .

We need to find the distance between the tops .

Applying Pythagoras theorem here ;

Distance between the tops of the towers = √[ { Distance between bases }² + { difference in height }² ]

=> √ ( 81 + 64 )

=> √ 145 m .

This is the required answer.

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Answer 2

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Given:

Two poles AD and CE of height 6 m, 11 m respectively.

Distance between the feet of two poles (DC) = 12 m

AD = BC = 6 m

BE = CE - BC = 11- 6 = 5 m

To prove: Find AE

Proof: According to Pythagoras theorem,

AE^2 = AB^2 + BE^2

AE^2 = 12^2 + 5^2 = 169

AE = 13.

∴ Distance between the tops of two poles = 13 m.

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