Two poles 15m high and 6m high are placed opposite to each other across a 8m long
road. Find the distance between their tops.
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Answer:
Let Pole A be 20 m and Pole B be 15 m high. Let the feet of Af and Bf be on level ground and 12 m apart.
Draw a horizontal line from the top of Pole B to the Pole A to meet Pole A at C. This line will meet Pole A at a point (20–15) = 5 m below the top of Pole A or AC = 5 m.
We have a right angled triangle ABC where BC = 12 m and AC = 5 m. By Pythagoras theorem AB = {12^2+5^2]^0.5 = 13 m.
Thus the top ends of the two poles are 13 m apart.
Step-by-step explanation:
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