CBSE BOARD X, asked by Anonymous, 3 months ago

Two poles 15m high and 6m high are placed opposite to each other across a 8m long
road. Find the distance between their tops.​

Answers

Answered by Sakhtlondi
3

\huge \mathsf{\orange {\underline {\purple {\underline { Required \ answer \ ♡ \  :- }}}}}

Given :-

Two poles AD and CE of height 6 m, 11 m respectively.

Distance between the feet of two poles (DC) = 12 m

AD = BC = 6 m

BE = CE - BC = 11- 6 = 5 m

To prove: Find AE

Proof: According to Pythagoras theorem,

AE² = AB² + BE²

AE² = 12² + 5² = 169

AE = 13.

\sf\red{∴ \  Distance  \ between \  the  \ tops \ of  \ two \  poles \  = \  13 m.}

Answered by ItzDazzingBoy
12

Answer:

Two poles AD and CE of height 6 m, 11 m respectively.

Distance between the feet of two poles (DC) = 12 m

AD = BC = 6 m

BE = CE - BC = 11- 6 = 5 m

To prove: Find AE

Proof: According to Pythagoras theorem,

AE² = AB² + BE²

AE² = 12² + 5² = 169

AE = 13.


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