Question

Two poles 15m high and 6m high are placed opposite to each other across a 8m long
road. Find the distance between their tops.​

Answer 1

$\huge \mathsf{\orange {\underline {\purple {\underline { Required \ answer \ ♡ \ :- }}}}}$

Given :-

Two poles AD and CE of height 6 m, 11 m respectively.

Distance between the feet of two poles (DC) = 12 m

AD = BC = 6 m

BE = CE - BC = 11- 6 = 5 m

To prove: Find AE

Proof: According to Pythagoras theorem,

AE² = AB² + BE²

AE² = 12² + 5² = 169

AE = 13.

$\sf\red{∴ \ Distance \ between \ the \ tops \ of \ two \ poles \ = \ 13 m.}$

Answer 2

Answer:

Two poles AD and CE of height 6 m, 11 m respectively.

Distance between the feet of two poles (DC) = 12 m

AD = BC = 6 m

BE = CE - BC = 11- 6 = 5 m

To prove: Find AE

Proof: According to Pythagoras theorem,

AE² = AB² + BE²

AE² = 12² + 5² = 169

AE = 13.