Question

Two poles 16m and 40m high are standing on the ground. If their feet are 7m apart. Find the
distance between their tops.​

Answer 1

Answer:

here base,b = 7m

height,a= 40-16 = 24m

let h be the hypotenuse

then by Pythagoras theorem

h = √(7^2 + 24^2) = 25m

So distance between their tops is 25m

Answer 2

Step-by-step explanation:

Let te length of two poles be AB and CD be 16 and 4 m.

Length of B is 7 m

Let the point E on the pole CD which is equidistant as the pole AB.

As the two pole are parallel

the distance between CE = CD - AB

= 40 - 16

= 24m

The ∆ ACE is an right angled triangle

so , AC² = AE² + CE²

AC² = 7²+ 24²

AC² = 625

AC =√625

AC = 25

hope it's will helps

Mark Brainliest if it helps you.....