two poles,18 m and 13 m high,stands upright in a playground. their feet are 12 m apart, find the distance between their tops??
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★ Correct Question:-
Two poles, 13 m and 18 m high stand upright on a playground. If their feet are 12 m apart, find the distance between the tops.
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★ Given:-
Height of two poles = 13 m, 18 m
Their feet = 12 m
★ To Find:-
The distance between their tops.
★ Solution:-
Let AB and CD be two poles of the height 13 m and 12 m and the distance between their feet, BD = 12 m. A || BD.
Then,
CE = DC - DB
= (DC - DE)
= (18 - 13) m = 5 m
In right angled ∆AEC,
AE = 12 m, CE = 5 m
By Pythagoras theorem,
AC² = AE² + CE²
⇒ AC² = (12² + 5²)
⇒ AC² = (144 + 25)
⇒ AC² = 169
⇒ AC² = (13)²
⇒ AC = 13
Hence, the distance between the tops of the poles = 13 m
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