Question

two poles 18m and 13m high stand upright in a playground if there feet are 12m apart find the distance between their tops

Answer 1

In quad. ABCD
AD=18m,BC=13m,CD=12m

In quad. BCDE
ED=13m,BC=13m,BE=12m

In ∆ ABE
AE=AD-ED
=18-13=5m
BE=12m
AB is a hypotenuse.
AB^2=AE^2+BE^2
=5^2+12^2
=25+144=169
AB=✓169
=✓13×13
AB=13m

Sorry for the improper diagram.

Answer 2

Answer:

Step-by-step explanation:

AB = 13 m, BE = 18 m and AB = 12 m (Given)

Since the opposite sides of the rectangle are equal. => BC= AB = 13 m

And DC = AB = 12m

We know, BE = 18 m => BC + CE = 18 m => CE = 18 – 13 = 5 m

Now, in right angled triangle CDE,

(Base)2

+ (Perpendicular)2

= (Hypotenuse)2

(DC)2

+ (CE)2

= (DE)2

(12)2

+ ( 5)2

= (DE)2

 (DE)2

= 144 + 25 = 169 = (13)2

 DE = 13 m

Therefore, Distance between the tops of two poles = 13 m