Math, asked by Sarithik, 1 year ago

Two poles 8m high 13m high are placed opposite to each other across a 12m long road. Find the distance between their tops

Chapter name: squares and square roots

Answers

Answered by anjali1800
21

Sol:
Given:
Two poles AD and CE of height 6 m, 11 m respectively.

Distance between the feet of two poles (DC) = 12 m

AD = BC = 6 m

BE = CE - BC = 11- 6 = 5 m

To prove : Find AE

Proof : According to Pythagoras theorem,

AE2 = AB2 + BE2

AE2 = 122 + 52 = 169

AE = 13.

∴ Distance between the tops of two poles = 13 m.

same as this

Answered by vinod04jangid
2

Answer:The distance between their tops of the poles is 13 m.

Step-by-step explanation:

Given:Two poles 8 m high 13 m high are placed opposite to each other across a 12 m long road.

To find:We have to find the distance between their tops.

Explanation:

Step 1:Let the height of poleAB is 8 m and height of pole CD id 13 m and distance between the poles from bottom BD

Step 2:According to the diagram the height of AB = DE = 8 m and

BD = AE respectively.

∴           EC = CD - DE

i.e.        EC = 13 - 8

            EC = 5 m.

Step 3:On applying the pythagoras theorem in ΔACE.We get

                 (AC)^{2} = (AE)^{2} +(EC)^{2}

                 (AC)^{2} = (12)^{2} +(5)^{2}

                 (AC)^{2} = 144+25

                 (AC)^{2} = 169

                     AC =\sqrt{169}

                     AC =13 m

∴ The distance between their tops of the poles is 13 m.

Concept:Pythagoras Theorem-Pythagoras theorem states that “In any right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides of that triangle“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. The hypotenuse is the longest side, as it is opposite to the angle 90°.

#SPJ2

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