Question

Two poles AB = 6 m and CD = 11 m stand on a ground as shown in the figure. If BC = 12 m, then AD is equal to 1. 13 m 2. 15 m 3. 17 m 4. 18 m​

Answer 1

Answer:

13m

Step-by-step explanation:

Two poles of height 6m and 11m stands on a plane ground, if the distance between their feet is 12m. Find the distance between their tops. Hence, the distance between the tops of the poles is 13m.

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Answer 2

Given :

height of first pole = AB= 6 m

height of second pole = CD = 11m

Distance between BC = 12 m

To find : Distance between AD

Solution :

Draw a line AE perpendicular to DC i.e. AE ⊥ DC

AE = AC = 12 m

AB = EC = 6 m

Now, DE = DC - EC

DE = 11 - 6

DE = 5 m

Since ∠AED = 90 as AE ⊥ DC

Using Pythagoras theorem in right angle,

(Hypotenuse) = (height )+ (base)

BD² = DE² + AE²

BD² = 5² + 12²

BD² = 25 + 144

BD² = 169

BD = 13

∴ Distance between AD is 13 m.