Question

Two poles AB and PQ of the same height 35m are standing opposite each other on either side of the road. The angles of elevation of the top of the poles, from a point C between them on the road, are 60° and 30° respectively. Find the distance between the poles.​

Answer 1

Answer:

refer to the attachment

Answer 2

Step-by-step explanation:

Answer:

2013 m.

Step-by-step explanation:

Here is your solution

Given:

AB and CD be the two poles of equal height.

Their heights be H m.

BC be the 80 m wide road.

P be any point on the road.

Let,

CP be x

BP = (80-x).

Also, ZAPB = 60° and <DPC = 30°

In right angled triangle DCP,

Tan 30° CD/CP

=> h/x=1/√3

→ h = x/√3 ---------- (1)

In right angled triangle ABP

Tan 60° AB/AP

h/(80-x) = √3

→ h = √3(80-x)

⇒> x/√3 = √3(80-x)

⇒ x = 3(80 - x)

⇒ x = 240 - 3x

⇒ x + 3x = 240

⇒ 4x = 240