Question

two poles are standing opposite to each other on the either side of the road which is 90 feet wide.the angle of elevation from bottom of first pole to top of second pole 45 the angle of elevation bottom of second pole to top of first pole is 30 , find the height of poles

Answer 1

Answer:

Step-by-step explanation:

Let the two poles be AB and CD

So, length of pole = AB =CD

length of road = 90 m

So, BC = 90 m

let point P be a point on the road between the poles

poles are perpendicular to ground

∠ABP = 90° , ∠DCP =90°

IN a right Δ DPC

tan P = CD/CP

tan 30°= CD/CP

1/ √3 = CD/CP

CP / √3 = CD ...(1)

in right Δ APB

tan P = AB/PB

tan 45° = AB /PB

1× PB = AB

PB =AB

CD = BP...(2)

From (1) & (2)

CP/ √3=BP

CP = BP / √3

Now BC = BP + CP

90 = BP + BP/√3

90 = BP + 1.732 BP

90 = 2.732 BP

BP = 32.9 m

Now CP = BC- BP

CP = 90 - 32.9

CP = 57.1 m

From CD = BP

so CD = 32.9m

Answer 2

Step-by-step explanation:

then the answer is 32.9 cm