Two poles
cast shadow 12 m and 14 m
resp. If height of one is 48
m,what can be possible height
of second.
Answers
Answered by
58
Answer:
ANSWER
Let AE be a pole of 10 m and BD be the another pole of 16 m and DE be the wire.
From the figure,
CD=16−10=6 m
Now,
In △CDE,
sin30∘=DECD
DE=2×6=12 m.
Hence, this is the answer.
Answered by
7
Step-by-step explanation:
Height of pole=AB=6 m
Length of shadow of pole =BC=4 m
Length of shadow of tower=EF=28 m
In △ABC and △DEF
∠B=∠E=90
∘
both 90
∘
as both are vertical to ground
∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)
∴△ABC∼△DEF by AA similarity criterion
We know that if two triangles are similar, ratio of their sides are in proportion
So,
DE
AB
=
EF
BC
⇒
DE
6
=
28
4
⇒DE=6×7=42 m
Hence the height of the tower is 42 m.
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