Question

two poles having height 7m and 13m respectively are placed on the same level 8m apart from each other. find the distance between their tops​

Answer 1

Answer:

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Answer 2

Answer:

Let AB and CD be the given vertical poles of heights 7m and 13m respectively. Distance BD between the feet of the poles is 8m.

Draw AE || BD meeting CD at E. The , ABDE is a rectangle.

ED = AB = 7m

CE = CD - ED = (13-7)m = 6m

AE = BD = 8m

In right triangle AEC , we have

AC² = AE² + EC²

AC² = (8m)² + (6m)² = (64 + 36)m² = 100 m²

$AC \: = \sqrt{100} = \: 10m$

Hence, the distance between the two tops of the two poles are 10m