Question

Two poles of 10m and 15m stand upright on the plane ground. If the distance between the tops is 13, find the distance between their feet

Answer 1

$<b> <I>$

Hey there !!

→ Let the two poles AB and CD are stand upright on the ground of 15m and 10m respectively.

→ AB is the distance between the tops of two poles is of 13m.

→ And, DB is the distance between their feet.

▶Now,

=> AE = AB - BE
=> AE = 15 - 10 . [ BE = CD ]
=> AE = 5m.

In ∆AEC,

➡ By Pythagoras theorem,

=> ( AC )² = ( AE )² + ( CE )².

=> (13)² = (5)² + (CE)².

=> 169 = 25 + (CE)².

=> (CE)² = 169 - 25.

=> CE = √144.

=> CE = 12m.

And, CE = BD.

So, BD = 12m. ( Distance between their feet ).

✔✔Hence, it is solved ✅✅.

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$\huge \bf{ \# \mathbb{B}e \mathbb{B}rainly.}$

Answer 2

Find the difference between the height of the 2 poles:

Difference = 15 - 10 = 5m

Given that the difference in height is 5m and the the slanted length between the two tops is 13 m, we can use Pythagoras theorem to find the distance between the two poles.

Find the distance between the feet of the two poles:

a² + b² = c²

5² + b² = 13²

b² = 13² - 5²

b² = 144

b = 12 m

Answer: The distance is the two pole is 12 m