Question

Two poles of 15m and 23m height stand upright on a plane ground. If the distance between their tops is 17m, then the distance between their feet is​

Answer 1

Answer:

Hey there !!

→ Let the two poles AB and CD are stand upright on the ground of 15m and 10m respectively.

→ AB is the distance between the tops of two poles is of 13m.

→ And, DB is the distance between their feet.

▶Now,

=> AE = AB - BE

=> AE = 15 - 10 . [ BE = CD ]

=> AE = 5m.

In ∆AEC,

➡ By Pythagoras theorem,

=> ( AC )² = ( AE )² + ( CE )².

=> (13)² = (5)² + (CE)².

=> 169 = 25 + (CE)².

=> (CE)² = 169 - 25.

=> CE = √144.

=> CE = 12m.

And, CE = BD.

So, BD = 12m. ( Distance between their feet ).

✔✔Hence, it is solved ✅✅.

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THANKS