Two poles of 8m and 14m stand upright on a plane ground. If the distance between two tops is 10m. Find the distance between their feet.
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Question :-
Two poles of 8m and 14m stand upright on a plane ground. If the distance between two tops is 10m. Find the distance between their ffeet
Answér :-
Let PQ and AC are two poles having height 8 m and 14 m respectively.
i.e. PQ = 8 m and AB = 14 m
The distance between their feet is 10 m
i.e. PA = 10 m.
Now, from the figure,
BC = 6 m and BQ = 12 m
The triangle CBQ is right-angled.
Applying Pythagoras Theorem, we get
↪(CQ)² = (BC)² + (BQ)²
↪(CQ)² = (6)2 + (12)2
↪(CQ)² = 36 + 144
↪(CQ)² = 180
↪CQ = √(180)
↪CQ = 6√5
Since distance can not be negative,
So, CQ = 6√5 m
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