Math, asked by mayur4266, 11 months ago

two poles of equal heights are on 2sides of highway 30m abide. the angle of elevation of the top of 2 poles from a point between them are such that their tangent ratios are 1 and 1/2 find their height?​

Answers

Answered by Prayasdgr8
0

Let AB and CD be the two poles of equal height standing on the two sides of the road of width 80 m.

AC = 80 m Let AP = x then PC = 80 – x P is a point on the road from which the angle of elevation of the top of tower AD is 60°, also, the angle of depression of the point P from the point B is 30°.

∠BPA = 60° and ∠DPC = 30° Draw a parallel line from DS to CA. ∠SDP = ∠DPC = 30°.

To Find : The height of the poles and the distance of the point P from both the poles.

From right

△PAB: tan 60° = AB/AP √3 = h/x or h = x√3 …(1)

From right △PCD: tan 30° = AB/AP 1/√3 = h/(80-x) or h = (80-x)/√3 …(2) Form (1) and (2),

we have (80-x)/√3 = x√3 80 – x = 3x x = 20

Form (1): h = (20)√3

Therefore, Height of each pole = (20)√3 m Distance of pole AB from point P = 20 m Distance of pole CD from point P = 80 – 20 = 60.

Answered by keithsymonm
0

Answer:

kala mo di masakit yung pinag sasabi mo sakin na patay gutom eh ikaw ng inulam nyo kalapati eh

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