Two poles of equal heights are standing on either side of the road; which is 80 m wide. From a
point between two poles on the road angle of elevtion of the tops of poles are 60° and 30°
respectively. Find the height of the poles and distance of the point from poles.
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Width of road is 90 ft
Heights of the pole are in the ratio 1 : 2
Angle of elevation of poles = 60°
Heights of the poles
→ Let the height of AB be x
→ Let the height of ED be 2x
→ Let CD = y, BC = 90 - y
→ Consider Δ ABC
x = ( 90 - y) √3
→ Consider Δ EDC
→ The LHS of equation 1 and 2 are equal. Therefore RHS must also be equal.
→ Cancelling x on both sides,
y = 180 - 2y
3y = 180
y = 60
→ Substitute the value of x in equation 2
√3 = 2x/60
60√3 = 2x
→ Hence height of ED = 2x = 60√3 ft
→ Height of AB = x = (60√3)/3 = 30√3 ft
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