Question

Two poles of equal heights are standing on either
side of a road of width so feet from a point
on the road the angle of evet elevation of the
poles is 60° & 30°calculate the height of the
Pole & distance of the point of the road
from the poles​

Answer 1

Answer:

Step-by-step explanation:

Here is your solution

Given:-

AB and CD be the two poles of equal height.

Their heights be H m.

BC be the 80 m wide road.

P be any point on the road.

Let ,

CP be x m,

BP = (80 – x) .  

Also, ∠APB = 60° and ∠DPC = 30°

In right angled triangle DCP,  

Tan 30° = CD/CP  

⇒ h/x = 1/√3  

⇒ h = x/√3 ---------- (1)  

In right angled triangle ABP

Tan 60° = AB/AP  

⇒ h/(80 – x) = √3

⇒ h = √3(80 – x)  

⇒ x/√3 = √3(80 – x)  

⇒ x = 3(80 – x)  

⇒ x = 240 – 3x

⇒ x + 3x = 240

⇒ 4x = 240

⇒ x = 60  

Height of the pole, h = x/√3 = 60/√3 = 20√3.  

Thus, position of the point P is 60 m from C and height of each pole is 20√3 m.

hope it helps you

Answer 2

Answer:

nothing ,,,,, and you ,,,,,,,,