Two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide. From a point between them on the road, the angles of elevation of the top of the poles are 60 digree and 30 digree, respectively. Find the height of the poles and the distance of the point from the poles.
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To find the distance of the point from the poles just put in the value of x which is 40 and you will get the answer.
Hope it helped!
Aryan Jha
Hope it helped!
Aryan Jha
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Step-by-step explanation:
Solution
The values we have,
AB = 80 cm
AC = BD = h
AP = x and BP = 80 - x
→ Perpendicular/Base = tan∅
→ AC/AP = tan 30°
→ AC/x = 1/√3
→ AC = x/√3
→ BD/BP = tan 60°
→ BD/(80 - x) = √3
→ BD = √3(80 - x)
Since, AC = BD
→ x/√3 = √3(80 - x)
→ x = 240 - 3x
→ 4x = 240
→AP = x = 60
So, BP = (80 - 60) = 20
→ AC = 60/√3
→ AC = 60√3/3
→ AC = BD = 20√3
Answer
Height of both poles is 20√3 m and point is 60 m away from left pole and 20 m away from right pole.
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