Question

Two poles of height 100 m and 109 m stand vertically upright on the surface of the ground. If the distance between their feet is 40 m, what is the distance between their tops ?​

Answer 1

Answer:

let ab be the first pole cd be the second pole

if ab=100m

cd=109m

bc=40m

then,

mark a line ae on cd which is parallel to bc

so ae=40m

ed=109-40

ed=9m

we can observe that aed is right angle triangle,we know two side(ae=40m and ed=9m)

ad is the hypotenuse

to find other side we should use Pythagoras theorem

Here,

ad^=ae^+ed^

ad^=40^+9^

ad^=1600+81

ad^=1681

ad=_/1681

ad=41m

•°•distance between their tops is 41m

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