Question

Two poles of height 13 m and 7 m respectively stand vertically on a
plane ground at a distance of 8 m from each other. The distance between
their tops is
a) 9 cm b) 10 cm
c) 11 cm
d) 12 cm​

Answer 1

$\textbf{\huge{\red{Solution}} }$

${ad}^{2} = {dc}^{2} + {ac}^{2} \\ = {8}^{2} + {6}^{2} \\ 64 \: + \: 36 = 100 \\ ad \: = \sqrt{100} = \: 10$

so ur answer is option B 10

Answer 2

$\bf{\underline{Question:-}}$

Two poles of height 13 m and 7 m respectively stand vertically on a

plane ground at a distance of 8 m from each other. The distance between

their tops is

a) 9 cm

b) 10 cm

c) 11 cm

d) 12 cm

$\bf{\underline{Solution:-}}$

• Let AB and DE be the two poles.

According to the question:

• AB = 13 m
• DE = 7 m

Distance between their bottoms = BE = 8 m Draw a perpendicular DC to AB from D, meeting AB at C.

We get:

DC = 8m, AC = 6 m

Applying, Pythagoras theorem in right-angled triangle ACD,

$\bf → AD^2 = DC^2 + AC^2$

$\bf → AD^2 = 8^2 + 6^2$

$\bf → AD^2 = 64 + 36$

$\bf → AD^2 = 100$

$\bf → AD = \sqrt{100}$

$\bf → AD = 10$

$\bf{\underline{Hence:-}}$

• The distance between their top is 10cm

_____________________

√√ Option ( b ) is correct √√