Question

two poles of height 18 and 13 M understand upright is a playground if their feet are 12 m apart find the distance between their tops

Answer 1

draw the figure of this question yourself so that it is easy to understand...


AB and PQ are the two poles of height 18 me and 13 me respectively.
since the distance between the poles is 12 me then

distance between their foots using Pythagoras theorem will be

AP²=12²+5²,

AP²=144+25,

then

AP²=169 ,

AP=√169,

hence

AP=13 me

Answer 2

★ Correct Question:-

Two poles, 13 m and 18 m high stand upright on a playground. If their feet are 12 m apart, find the distance between the tops.

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★ Given:-

Height of two poles = 13 m, 18 m

Their feet = 12 m

★ To Find:-

The distance between their tops.

★ Solution:-

Let AB and CD be two poles of the height 13 m and 12 m and the distance between their feet, BD = 12 m. A || BD.

Then,

CE = DC - DB

= (DC - DE)

= (18 - 13) m = 5 m

In right angled ∆AEC,

AE = 12 m, CE = 5 m

By Pythagoras theorem,

AC² = AE² + CE²

⇒ AC² = (12² + 5²)

⇒ AC² = (144 + 25)

⇒ AC² = 169

⇒ AC² = (13)²

⇒ AC = 13

Hence, the distance between the tops of the poles = 13 m