Question

two poles of height 6 CM and 11 M stand on a plane ground .if the distance between their feet is 12m find the distance between their tops with full method ​

Answer 1

Answer:

Given parameters

The two poles

AB = 11 m and CD = 6m

Distance between both poles (BD) = 12m

Difference lengths of poles = 5m

Then, create a line segment CE parallel to line BD

Draw the line (CE) to the longer pole perpendicularly from the top of the shorter pole and also connect the tops of the poles, clearly forming a right-angled triangle.

From the figure

AE = AB – CD

AE = 11 – 5

AE = 6 m

According to the Pythagoras theorem,

(AC)2 = (AE)2 + (EC)2

(AC)2 = 62 + 122

(AC)2 = 36 + 144

(AC)2 = 169

AC = 13 m

The distance between the tops of two poles is 13 m.

Answer 2

Answer:

13

Step-by-step explanation:

distance between feets of towers = 12m

difference of height between towers = 5m

to find the distance between their tops use Pythagoras theorem

distance between their tops is the hypotenuse of traingle formed by diff of height between towers and difference between their feet

= √((12^2) + (5^2))

=13