Question

Two poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance between their foot is 12 m, the distance between their tops is
(a) 12 m
(b) 14 m
(c) 13 m
(d) 11 m

Answer 1

Answer:

The distance between their tops is 13 m.

Among the given options option (c) is 13 cm is the correct answer.

Step-by-step explanation:

Given:

CE = 11 m, DC = AB = 12m and AD = BC = 6 m

Construction: Draw AB ⊥ EC

BE = EC – BC

BE  = 11 – 6  

BE = 5 m

In ∆ABE,

AE² = AB² + BE²

[By using Pythagoras theorem]

AE² = 12² +5²

AE² = 144 + 25  

AE² = 169

AE = √169  

AE = 13 m

Hence, the distance between their tops is 13 m.

HOPE THIS ANSWER WILL HELP YOU…

Answer 2

Heya!

Here is ur answer...

Given,

Height of the 1st pole(AB) = 11m

Height of the 2nd pole (CD)= 6m

The distance between their foots(BC) = 12m

Now, From the figure (in attachment)

□DEBC is a rectangle

Therefore,

EB = DC = 6m

ED = BC =12m

And,

AE = AB-EB

AE = 11 - 6

AE = 5m

In Triangle AED,

From pythagoras theorem,

AD^2 = AE^2 +ED^2

AD^2 = 5^2 + 12^2

AD^2 = 25 +144

AD^2 = 169

AD = square root of 169

AD = 13

Therefore,

Distance between the top of the poles is

(c) 13m

Hope it helps u..